Neon Number

#include<stdio.h>

int main()
{
    int n, sq, i, sum = 0;

    printf("Enter the number:");
    scanf("%d", &n);

    sq = n * n;

    for (i = sq; i > 0; i = i / 10)
        sum = sum + i % 10;

    if (sum == n)
        printf("%d is a neon number.", n);
    else
        printf("%d is not a neon number.", n);

    return 0;
}

OUTPUT

Enter the number:9
9 is a neon number.