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Tuesday 7 November 2017

HCF & LCM

#include <stdio.h>

int main()
{

    int a, b, x, y, t, gcd, lcm;

    printf("Enter two integers\n");
    scanf("%d%d", &x, &y);

    a = x;
    b = y;

    while (b != 0)
    {
        t = b;
        b = a % b;
        a = t;
    }

    gcd = a;
    lcm = (x * y) / gcd;

    printf("Greatest common divisor of %d and %d = %d\n", x, y, gcd);
    printf("Least common multiple of %d and %d = %d\n", x, y, lcm);

    return 0;

}
OUTPUT
Enter two integers
2 5
Greatest common divisor of 2 and 5 = 1
Least common multiple of 2 and 5 = 10

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